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HCPL3150 Folha de dados(PDF) 11 Page - Agilent(Hewlett-Packard)

Nome de Peças HCPL3150
Descrição Electrónicos  0.5 Amp Output Current IGBT Gate Drive Optocoupler
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Fabricante Electrônico  HP [Agilent(Hewlett-Packard)]
Página de início  http://www.home.agilent.com
Logo HP - Agilent(Hewlett-Packard)

HCPL3150 Folha de dados(HTML) 11 Page - Agilent(Hewlett-Packard)

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1-207
Figure 26. HCPL-3150 Typical Application Circuit with Negative IGBT Gate Drive.
Selecting the Gate Resistor
(Rg) to Minimize IGBT
Switching Losses.
Step 1: Calculate Rg Minimum
From the IOL Peak Specifica-
tion. The IGBT and Rg in Figure
26 can be analyzed as a simple
RC circuit with a voltage supplied
by the HCPL-3150.
(VCC – VEE - VOL)
Rg
≥ –––––––––––––––
IOLPEAK
(VCC – VEE - 1.7 V)
= ––––––––––––––––
IOLPEAK
(
15 V + 5 V - 1.7 V)
= ––––––––––––––––––
0.6 A
= 30.5
The VOL value of 2 V in the pre-
vious equation is a conservative
value of VOL at the peak current
of 0.6 A (see Figure 6). At lower
Rg values the voltage supplied by
the HCPL-3150 is not an ideal
voltage step. This results in lower
peak currents (more margin)
than predicted by this analysis.
When negative gate drive is not
used VEE in the previous equation
is equal to zero volts.
Step 2: Check the HCPL-3150
Power Dissipation and
Increase Rg if Necessary. The
HCPL-3150 total power dissipa-
tion (PT) is equal to the sum of
the emitter power (PE) and the
output power (PO):
PT = PE + PO
PE = IF VF Duty Cycle
PO = PO(BIAS) + PO (SWITCHING)
= ICC(VCC - VEE)
+ ESW(RG, QG)f
For the circuit in Figure 26 with IF
(worst case) = 16 mA, Rg =
30.5
Ω, Max Duty Cycle = 80%,
Qg = 500 nC, f = 20 kHz and TA
max = 90
°C:
PE = 16 mA1.8 V0.8 = 23 mW
PO = 4.25 mA20 V
+
4.0
µJ20 kHz
=
85 mW + 80 mW
=
165 mW
>
154 mW (PO(MAX) @ 90°C
=
250 mW
20C4.8 mW/C)
PO Parameter
Description
ICC
Supply Current
VCC
Positive Supply Voltage
VEE
Negative Supply Voltage
ESW(Rg,Qg)
Energy Dissipated in the HCPL-3150 for each
IGBT Switching Cycle (See Figure 27)
f
Switching Frequency
PE
Parameter
Description
IF
LED Current
VF
LED On Voltage
Duty Cycle
Maximum LED
Duty Cycle
+ HVDC
3-PHASE
AC
- HVDC
0.1 µF
VCC = 15 V
1
3
+
2
4
8
6
7
5
HCPL-3150
Rg
Q1
Q2
VEE = -5 V
+
270
+5 V
CONTROL
INPUT
74XXX
OPEN
COLLECTOR


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