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TS4994IST Folha de dados(PDF) 24 Page - STMicroelectronics |
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TS4994IST Folha de dados(HTML) 24 Page - STMicroelectronics |
24 / 31 page TS4994 Application Information 24/31 4.6 Power dissipation and efficiency Assumptions: l Load voltage and current are sinusoidal (Vout and Iout) l Supply voltage is a pure DC source (Vcc) Regarding the load we have: and and Therefore, the average current delivered by the supply voltage is: The power delivered by the supply voltage is: Psupply = Vcc IccAVG (W) Then, the power dissipated by each amplifier is Pdiss = Psupply - Pout (W) and the maximum value is obtained when: and its value is: Note: This maximum value is only dependent on power supply voltage and load values. The efficiency is the ratio between the output power and the power supply The maximum theoretical value is reached when Vpeak = Vcc, so V out = V PEAK sinω t (V) I out = V out R L -------------- (A) P out = VPE AK 2 2RL ---------------------- (W) ICC AVG = 2 VPEAK πRL -------------------- (A) P diss 22V CC π R L ------------------------ P out Pou t – = ∂Pdiss ∂P out ---------------------- = 0 ) W ( R Vcc 2 max Pdiss L 2 2 π = η = P out P supply --------------------- = π VPEAK 4VCC ----------------------- π 4 ----- = 78.5% |
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